Fixed ltree parentPath issue + removed get_ltree SQL function. Thanks to Sonia Zorba.

/*

    Author: Sonia Zorba

    Email: sonia.zorba@inaf.it

*/

-- Returns the ltree path for a given os_path

CREATE OR REPLACE FUNCTION get_ltree_path(input_os_path character varying) RETURNS ltree AS $$

BEGIN

    RETURN 

    ltree_path FROM (

        SELECT node_id, string_agg(name, '/') AS os_path, first_value(path) over() ltree_path FROM (

            SELECT f1.name, f2.path, f2.node_id

            FROM Node f1 

            JOIN Node f2 ON f1.path @> f2.path

            WHERE f2.name = (string_to_array(input_os_path, '/'))[cardinality(string_to_array(input_os_path, '/'))]

            ORDER BY f2.node_id, length(f1.path::varchar) ASC

        ) AS t1 GROUP BY node_id, path

    ) AS t2 WHERE os_path = input_os_path;

END;

$$ LANGUAGE plpgsql;

    Email: sonia.zorba@inaf.it

*/

-- Alternative way to obtain the os_path

-- This view allows to obtain the the ltree_path from the os_path

-- Example query:

-- SELECT path FROM Node n JOIN node_os_path o ON n.node_id = o.node_id WHERE os_path = '/curban/store';

CREATE VIEW node_os_path AS

SELECT node_id, '/' AS os_path FROM Node WHERE path = ''

UNION

        if self.conn:

            out = open("db_connector_log.txt", "a")

            #print(f"parentOSPath: {parentOSPath}")

            self.cursor.execute("SELECT get_ltree_path(%s)", (parentOSPath,))

            self.cursor.execute("SELECT path FROM Node n JOIN node_os_path o ON n.node_id = o.node_id WHERE os_path = %s;", (parentOSPath,))

            result = self.cursor.fetchall()

            for i in result:

                out.write(f"queryResult: {i}\n")